Mathematics: chandler bought a bmw for $53,900 in 2018 one year later the value of the car was $25,300 what was the percent of decrease of the value of the car round to the nearest whole percent

chandler bought a bmw for $53,900 in 2018 one year - id5390020188567884, rodneisha1313

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blink182lovgabbie

29.11.2020

Mathematics

-53.0612244898%

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simple math

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rorofhs2009

19.02.2020

Mathematics

$\bf \stackrel{\textit{Sam invested the first year}}{x} \qquad \qquad \stackrel{\textit{2nd year is \$2,000 less than \underline{x}}}{x-2000} \\\\\\ \stackrel{\textit{3rd year is \$1,000 more than \underline{x}}}{x+1000}\qquad \qquad \boxed{\stackrel{\textit{Sam total investment}}{(x)+(x-2000)+(x+1000)}}\\\\ -------------------------------\\\\ \stackrel{\textit{Sally invested the first year \$1000 less than \underline{x}}}{x-1000}$

$\bf \stackrel{\textit{2nd year is \$1500 less than \underline{2x}}}{2x-15000}\qquad \qquad \stackrel{\textit{3rd year is \$1400 more than \underline{x}}}{x+1400} \\\\\\ \boxed{\stackrel{\textit{Sally total investment}}{(x-1000)+(2x-1500)+(x+1400)}}$

$\bf \stackrel{\textit{Sam total investment}}{(x)+(x-2000)+(x+1000)}=\stackrel{\textit{Sally total investment}}{(x-1000)+(2x-1500)+(x+1400)} \\\\\\ 3x-1000=4x-1100\implies 100=x\impliedby \textit{Sam invested the first year} \\\\\\ \stackrel{\textit{Sally invested last year}}{x+1400}\implies 10+1400\implies 1500$

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chandler bought a bmw for $53,900 in 2018 one year later the value of the car was $25,300 what was the percent of decrease of the value of the car round to the nearest whole percent

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