Chord ac intersects chord bd at point p in circle z.

ap=3.5 in.
dp=4 in.
pc=6 in.

what is bp?

enter your answer as a decimal in the box.

1. To solve this exercise, you must use the "Intersecting chords theorem".

2. You have that:

AP=3.5 in
PC=6 in
DP=4 in

3. Then, by applying the "Intersecting chord theorem", you have:

(AP)(PC)=(BP)(DP)

4. When you substitute the values into (AP)(PC)=(BP)(DP), you obtain:

(3.5 in)(6 in)/BP(4 in)

5. Now, you must clear BP. Then:

(3.5 in)(6 in)/4 in=BP
21 in^2/4 in=BP

6. Therefore, the value of BP is:

BP=5.25 in

The perimeter to the nearest tenth is 18

Step-by-step explanation:

ok first since this is a square all sides are of equal length

next you need to do 2^2 plus 4^2= c^2

the side of the square being c of course

you get 4.5 if you round to the nearest tenth

4.5+4.5+4.5+4.5=18