Chris can be paid in one of two ways. Plan A is a salary of $490 per month, plus a commission of 9% of sales. Plan B is a salary of $826 per month, plus a commission of 3% of sales. For what amount of sales is Chris better off selecting plan A?

Step-by-step explanation:

Explanation:

First, when dealing with percents, "Percent" or "%" means "out of 100" or "per 100", Therefore x% can be written as

 x/100.

The expression for Plan A can be written as:

490+(9/100)s where s is the sales for the month.

The expression for Plan B can be written as:

826+(3/100)s

The question we are being asked is when is Plan A > Plan B. So, we can write and solve this inequality:

490+(9/100)s>826+(3/100)s

490+(9/100)s−490−(3/100)s>826+(3/100)s−490−(3/100)s

490−490+(9/100)s−(3/100)s>826−490+(3/100)s−(3/100)s

0+(9/100)s−(3/100)s>826−490+0

(9/100)s−(3/100)s>826−490

(9/100−3/100)s>336

(6/100)s>336

(100/6)×(6/100)s>(100/6)×336

s> 33600/6

s>5,600

 Plan A is better when sales for the month are greater than $5,600.

The probability is 0.89 or 89%

Step-by-step explanation:

Probability

There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.

We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.

The probability that a randomly chosen student plays basketball or baseball is:

Simplifying:

The probability is 0.89 or 89%