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khush77
30.06.2019 •
Mathematics
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. release your mouse button when the item is place. if you change your mind, drag the item to the trashcan. click the trashcan to clear all your answers. indicate in standard form the equation of the line passing through the given point and having the given slope. a(5, 5), m = 3
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Ответ:
Ответ:
We divide the given figure into four parts as shown in the attachment
First we calculate the area of the three small rectangle that make up of the given figure. These small rectangles are named ABCD, EFGH and IJKL
Area of the rectangle ABCD = AB * AC
AC = 6 inches
AJ =MN = 12 inches
BE = 5 and FI = 5
AJ = AB+BE+EF+FI +IJ
12 = AB + 5+EF +5 + IJ
12-10 = AB + EF + IJ
AB + EF + IJ = 2
Since all the three segments are equal, AB = EF = IJ = 2/3
Area of rectangle ABCD = AB*AC = 2/3 * 6 = 4 square inches
Similarly area of rectangle EFGH = 4 square inches
Similarly area of rectangle IJKL = 4 square inches
Area of these small rectangles are named ABCD, EFGH and IJKL = 4 +4 +4 = 12 square inches
Now we have the area of the last big rectangle AMNJ = AM* MN
MN = 12 inches and AM = MC - AC = 7 - 6 = 1 inch
area of the last big rectangle AMNJ = 12 *1 = 12 square inches
Total area = area of small rectangles + area of big rectangle
Total area = 12 + 12 = 24 square inches (Option A)