Coach a is offering her services for an initial $6,925 in addition to $450 per hour. coach b is offering her services for an initial $5,000 in addition to $725 per hour. when will the two coaches charge the same amount of money? the two coaches will charge the same amount of money after

The two coaches will charge the same amount of money after working for 11 hours

Step-by-step explanation:

Let us assume for m hours, they both will charge same amount.

For COACH A:

The initial Fee = $ 6,925

The per hour fee  = $450

So, the fees in m hours = m x ( Per hour fees) = m x ($450)  = 450 m

So, the total fees of Coach A in m hours = Initial Fee + fee for m hours

                                                                  = $ 6,925  + 450 m  

⇒ The total fees of Coach A in m hours  = $ 6,925  + 450 m  (1)

For COACH B:

The initial Fee = $ 5,000

The per hour fee  = $725

So, the fees in m hours = m x ( Per hour fees) = m x ($725)  = 725  m

So, the total fees of Coach B in m hours = Initial Fee + fee for m hours

                                                                  = $ 5,000  + 725 m  

⇒ The total fees of Coach B in m hours  =$ 5,000  + 725 m  (2)

Now, for m hours , they both charge the SAME AMOUNT fees

⇒$ 6,925  + 450 m  = $ 5,000  + 725 m    ( from (1) and (2))

or, 6925 - 5000 = 725 m - 450 m

or, 1925 = 175 m

or,m = 1925 / 175 = 11

or, m = 11

Hence, the two coaches will charge the same amount of money after working for 11 hours.

Let "the number" = x

3x - 6 = 45 is your equation

Solve for x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

Isolate the x. First, add 6 to both sides

3x - 6 (+6) = 45 (+6)

3x = 51

Isolate the x. Divide 3 from both sides

3x/3 = 51/3

x = 51/3

x = 17

17 is your answer for "a number".

hope this helps