Coach kent brings 3 quarts of sport drink to coccer practice he gives the same amount to each of his 16 players how many ouncesof the drink does each player get

Part.1
Given equation:
C(t) = -0.30 (t – 12)² + 40 

For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2

For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40

For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2

Part.2
Graph of the equation is given in the attachment.

Part.3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32

Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104