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mimigg0621
23.07.2019 •
Mathematics
Complete the steps of the derivation of the quadratic formula. step 2: step 3: step 4: step 5:
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Ответ:
To complete the derivation of the quadratic equation:
Given:
Add both sides
we have;
Taking square root both sides we have;
⇒![(x+\frac{b}{2a})= \pm \sqrt{\frac{b^2-4ac}{4a^2}}](/tpl/images/0123/1054/d75d8.png)
⇒![x+\frac{b}{2a} =\pm \frac{\sqrt{b^2-4ac}}{2a}](/tpl/images/0123/1054/f37de.png)
Subtract
from both sides we have;
Therefore, complete derivation for the quadratic equation is:
Step 1.
Step 2.
Step 3.
Step 4.
Step 5.
or
Ответ:
(x+b/2a)^2-[(b²-4ac)/4a^2]=0
Step 2
(x+b/2a)^2=(b²-4ac)/4a^2
Step 3
getting the square root of both sides we get
x+b/2a=√(b²-4ac)/4a^2
x+b/2a=+/-√(b²-4ac)/2a
Step 4
subtract b/2a from both sides we get:
x+b/2a-b/2a=-b/2a+/-√(b²-4ac)/2a
x=-b/2a+/-√(b²-4ac)/2a
Step 5
Simplifying the above by putting them under the same denominator we get
x=[-b+/-√(b²-4ac)]/2a
Ответ:
None.
All the four given measurements can form a triangle.
Step-by-step explanation:
Given;
first measurement, = 2m , 5m, 6m
second measurement, = 8m, 10m, 17m
third measurement, = 5m, 20m, 22m
fourth measurement, = 4m, 15m, 20m
For any of the three lengths to form a triangle, the sum of any two sides must be greater than the third side.
First measurement: 2m + 5m = 7m and 7m > 6m (can form a triangle)
Second measurement: 8m + 10m = 18m and 18m > 17m (can form a triangle)
Third measurement: 5m + 20m = 25m and 25m > 22m (can form a triangle)
Fourth measurement: 4m + 15m = 19m and 19m < 20m BUT
20 m + 15m = 35 m and 35 m > 4m (can form a triangle)
Therefore, all the four given measurements can form a triangle.