Complete the work shown to answer the question. p2 – 14p – 72 = 0 p2 – 14p = 72 p2 – 14p + 49 = 72 + 49 which describes the solutions of the equation? since 7 and 11 are both rational, the sum and difference are rational. since 14 and 11 are both rational, the sum and difference are rational. since 7 is rational and is irrational, the sum and difference are irrational. since is irrational and 11 is rational, the sum and difference are irrational.

Since 7 and 11 are both rational, the sum and difference are rational.

a. Since 7 and 11 are both rational, the sum and difference are rational.  

Step-by-step explanation:

p^2 – 14p – 72 = 0

p^2 – 14p = 72

p^2 – 14p + 49 = 72 + 49

p^2 – 14p + 7^2 = 11^2

(p - 7)^2 = 121

taking square roots in both sides

p - 7 = ± 11

This procedure was made knowing that 7 and 11 are both rational

The range of values for the sample mean is between a lower limit of 19 and an upper limit of 21.

Step-by-step explanation:

sample mean = 20

sd = 10

n = 25

standard error = 1

Lower limit of sample mean = sample mean - standard error = 20 - 1 = 19

Upper limit of sample mean = sample mean + standard error = 20 + 1 = 21

The range of values for the sample mean is between 19 and 21.