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Paigex3
04.09.2020 •
Mathematics
Consider a post office with two clerks. Three people: A, B, and C; enter simultaneously. A and B go directly to the two clerks, and C waits until either A or B leaves before beginning service with the free clerk. What is the probability A is the last customer to complete service when
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Ответ:
(1) Pr(A > B + C) = 0
(2)![\mathbf{\dfrac{1}{27}}](/tpl/images/0741/5873/9c86c.png)
Step-by-step explanation:
From the information given:
What is the probability A is the last customer to complete service when:
(1) the service time for each clerk is precisely ten minutes?
The probability (Pr) that A is the last customer can be computed as:
P( A > B + C )
if we recall, we are being told that the service time for each clerk is 10 minutes. As such, there is no occurrence of any event.
Therefore, the probability A is the last customer to complete service when the other customers had left will be :
Pr(A > B + C) = 0
(2) when the service time are (i) with probability(pr) 1/3, i=1,2,3?
when service time i are (1,2,3) with probability![\dfrac{1}{3}](/tpl/images/0741/5873/fd93e.png)
Then the event that A will be the last customer to complete service when the other two customers had left will occur when A = 3, B= 1, C= 1
Thus, the probability that A is the last customer to complete service when the other customers had left will be :
Pr ( A > B + C ) = Pr( A = 3, B = 1, C = 1)
Pr ( A > B + C ) =
given that the service times are independent
Pr ( A > B + C ) =![\begin {pmatrix} \dfrac{1}{3} \times \dfrac{1}{3} \times \dfrac{1}{3} \end {pmatrix}](/tpl/images/0741/5873/7bb63.png)
Pr ( A > B + C ) =![\mathbf{\dfrac{1}{27}}](/tpl/images/0741/5873/9c86c.png)
Ответ:
23
Step-by-step explanation:
got this answer bc bc i told myself 1/5 is one whole ad took 5 out of it and then subtracted 5-60 and then got 55 and after that i subtracted 55-32 and thats how i got my answer of 23