alexandroperez13
28.01.2020 •
Mathematics
Consider the equation 2x+8y=12
a- what is the graph of this equation
b. what is the slope of the lines parallel to the graph of this equation
c. what si the slope of the lines perpendicular to the graph of this equation
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Ответ:
6=x then you plug that back in, 12+8y=12
8y=0
y=0
(6,0)
Ответ:
2
yand2xy
2
⇒(−5x
2
y)(2xy
2
)
⇒−10x
3
y
3
⇒−10(xy)
3
Ans.