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Gabby2581
19.11.2020 •
Mathematics
Consider the function f(x)=2^x. A horizontal asymptote is a horizontal line that the graph of a function approaches but never touches. Horizontal lines on a graph are given by the equation y=constant value. So y=0 is the horizontal line on the x axis, y=1 is the horizontal line where y=1...etc .
Using -x values as your inputs, see what output value the function approaches as your input values get smaller and smaller. Use x=-5, x=-10, x=-20 ,...etc. as your inputs and see what value the output approaches but never reaches. This will be the asymptote for the graph of f(x)=2^x.
For your answer please state the output value that you approach but never touch.
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Ответ:
Ответ:
0.5 < x < 3
or (0.5, 3)
Step-by-step explanation:
-16t² + 56t + 2 = 26
Subtract both sides by 26
-16t² + 56t + 2 = 26
-26 -26
-16t² + 56t - 24 = 0
Divide both sides by -8 to simplify
(-16t² + 56t - 24)/8 = 0/8
2t² - 7t + 3 = 0
Factor
(x - 3)(2x - 1) = 0
Do this to find the x's
x - 3 = 0
+ 3 +3
x = 3
2x - 1 = 0
+ 1 + 1
2x = 1
2x/2 = 1/2
x = 0.5
0.5 < x < 3
This means the intervals will have to be between 0.5 and 3 seconds