mle531588
27.06.2019 •
Mathematics
Consider the function ƒ(x) = 3x2 + 6x + 5. write the function in the form of ƒ(x) = a(x – h)2 + k, where a, h and k are constants.
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Ответ:
f(x) = 3(x + 1)² + 2
Step-by-step explanation:
Use the method of completing the square
3x² + 6x + 5
= 3(x² + 2x) + 5
add/ subtract (half the coefficient of the x-term)² to x² + 2x
= 3(x² + 2(1)x + 1 - 1) + 5
= 3(x + 1)² - 3 + 5
f(x) = 3(x + 1)² + 2 ← in vertex form
Ответ: