Consider the Line L(t) = <2+t,5-4t>. Then L intersects: The x- axis at the point (3.25,0) when t = 5/4

The y- axis at the point (0, 13) when t = -2

The parabola y = x^2 at the points ___ and ___ when t = and

The parabola at the points and when and

Step-by-step explanation:

We have the following line written in parametric form :

with ∈ IR.

In order to find the intersection between and the parabola we know that '''' is the x-coordinate of the line and '''' is the y-coordinate of the line. Now, to solve this problem we need to find the values of '''' in which the intersection occurs. We can do this by replacing the components    '''' and '''' of in the equation of the parabola ⇒

= ( x component , y component ) = ( x , y ) ⇒

In the parabola : ⇒

Solving the equation we find that :

Using the quadratic formula with

, and

We find that the two possible values for t :

    and  

are and

This values and are the values of the parameter t where the line intersects the parabola so we can find the points by replacing the values of the parameter in the equation :

and

The final answer is

The parabola at the points and when and

We are looking for the probability of a number that is prime or greater than 4. To solve for this, we need to figure out what 'prime' is. Prime is a number that cannot be divided into any smaller factors (aside from 1). An example is 11. 11 cannot be divided by any smaller numbers. There are a total of 6 numbers on a six-sided dice. With this information, let's get started! First, we'll find how many prime numbers are before 4, since the question is asking for prime numbers OR a number greater than 4. 2 and 3 are both prime numbers. So far, we have 2/6. Now, we need to count how many numbers are greater than 4 on a dice. 5 and 6 are numbers greater than 4 on a dice. So far on this, we have 2/6. Now, sum up our fractions from the information we've gathered. 2/6 + 2/6 = 4/6. Your answer is 4/6 or 2/3 if simplified. I hope this helps!