Consider the partial construction of a line parallel to liner through point Q. What would be the final step in the construction?
Draw a line through P and S.
Draw a line through W and S.
Draw a line through Q and S.
Draw a line through T and S.

Option (3)

Step-by-step explanation:

To construct a line parallel to the line through point Q we will follow the following steps,

1). We join two points P (on the line) and point Q above the line PT with the help of a straightedge.

2). Now we will copy the angle QPT at point P with the help of a compass (Arcs as shown in the figure)

3). Finally we will join points Q and S to construct a line QS parallel to the line PT.

Therefore, Option (3) will be the answer.

Step-by-step explanation:

Surface area = lateral area + 2(area of base)

Lateral area = perimeter of base * height.

Because it is a isosceles right triangle, both sides are equal.

= 72

2 = 72. Divide both sides by 2

= 36.  Square both sides.

x = 6.

So the perimeter of the base = 6 + 6 + = 20.485281374239

Lateral area = 20.485281374239 * 7 = 143.397

Area of base is (1/2)base * height.

(1/2)(6)(6) = 18

Using the surface area formula

surface area = 143.397 + 2(18) = 179.4