Mathematics: Consider the quadratic equation x2=4x-5. how many solutions does the equation have

Consider the quadratic equation x2=4x-5. how

Ответ:

adrian128383

15.03.2022

$\bf x^2=4x-5\implies x^2-4x+5=0
\\\\\\
\begin{array}{lcccll}
& 1 x^2& -4 x& +5&=0\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}$

now, plugging in those values for the discriminant, we'd get

(-4)² - 4(1)(5).

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Ответ:

bellabrill

22.11.2021

Mathematics

Because there are no options I am going to say it would be x≥2 . :)

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Consider the quadratic equation x2=4x-5. how many solutions does the equation have

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