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miranda911
27.05.2020 •
Mathematics
Consider this system of equations. Which shows the first equation written in slope-intercept form?
2 (2y+10) = 7*
y=8
y = 7x-10
7
y=zx-5
y = 7x-5
o y = 1 x - 5
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Ответ:
Question:
Consider this system of equations. Which shows the first equation written in slope-intercept form?
½(2y + 10) = 7x.
y = 8.
A. y = 7x - 10
B. y = 7x/2 - 5
C. y = 7x - 5
D. y = 7x/4 - 5
C. y = 7x - 5
Step-by-step explanation:
Given
½(2y + 10) = 7x.
Required
Convert to slope intercept form.
To do this, we simply make y the subject of formula from the given equation
We start by writing out the equation
½(2y + 10) = 7x.
Then, we open the bracket
½ * 2y + ½ * 10 = 7x
2y/2 + 10/2 = 7x
y + 5 = 7x
Then, subtract 5 from both sides of the equation
y + 5 - 5 = 7x - 5
y = 7x - 5
The equation can't be simplified any further. So, we've arrived at a solution
Hence, the slope intercept form of ½(2y + 10) = 7x is y = 7x - 5
Ответ: