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mawawakaiii
03.02.2020 •
Mathematics
Correct answer only !
suppose company a produces packages of throat lozenges that are normally distributed with a mean of 38.2 individual lozenges and a standard deviation of 1.7 lozenges.
company b produces packages of throat lozenges that are normally distributed with a mean of 36.9 individual lozenges and a standard deviation of 2.4 lozenges.
select from the drop-down menus to correctly complete the statement.
choices are company a and company b
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Ответ:
B, A, B
Step-by-step explanation:
Let's find the z-score for both companies using the formula:![z=\dfrac{x-\mu}{\sigma}](/tpl/images/0494/5625/8ab38.png)
Company A:![z=\dfrac{43-38.2}{1.7}=\large\boxed{2.8}](/tpl/images/0494/5625/d34d1.png)
Company B:![z=\dfrac{43-36.9}{2.4}=\large\boxed{2.5}](/tpl/images/0494/5625/5cddc.png)
The z-score from Company B is closer to 0 than the z-score of Company A so it it more likely that a package of 43 lozenges is produced by Company B
Ответ:
A and B
Step-by-step explanation:
x²+6x+9=2
(x+3)^(2) =2
x= ±√2 -3
Therefore answer is A and B