james1110
james1110
25.12.2021 • 
Mathematics

Cos²θ⋅sin⁴θ=1/32 (2−cos2θ−2cos4θ+cos6θ)


Cos²θ⋅sin⁴θ=1/32 (2−cos2θ−2cos4θ+cos6θ)

Solved
Show answers

Ask an AI advisor a question