Jeileenrojas
15.01.2020 •
Mathematics
((cot^2theta)/(1+csctheta))=((1-sintheta)/(sintheta))
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Ответ:
cot^2theta = csctheta^2 - 1 = (csctheta - 1) (csctheta+1)
L.H.S = (csctheta - 1)(csctheta+1)/1+csctheta = cscstheta - 1 = R.H.S
Ответ:
960
Step-by-step explanation: