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23.01.2022 •
Mathematics
Create a system of equations of the form x ≡ c1 (mod n1) and x ≡ c2 (mod n2) that has more than one solution in 
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Ответ:
Step-by-step explanation:
it's hard, I tried to do it but it didn't work
Ответ:
Step-by-step explanation: You have to substitute the numbers in for x & y
(0, -5): YES
3x - 4y - 8 = 12
3(0) - 4(-5) - 8 = 12
0 + 20 - 8 = 12
20 - 8 = 12
12 = 12
(4, -2): YES
3x - 4y - 8 = 12
3(4) - 4(-2) - 8 = 12
12 + 8 - 8 = 12
20 - 8 = 12
12 = 12
(8, 2): NO
3x - 4y - 8 = 12
3(8) - 4(2) = 12
24 - 8 = 12
16 = 12
(-16, -17): YES
3x - 4y - 8 = 12
3(-16) - 4(-17) - 8 = 12
-48 + 68 - 8 = 12
20 - 8 = 12
12 = 12
(-1, -8): NO
3x - 4y - 8 = 12
3(-1) - 4(-8) = 12
-3 + 32 = 12
29 = 12
(-40, -34): NO
3x - 4y - 8 = 12
3(-40) - 4(-34) - 8 = 12
-120 + 136 - 8 = 12
16 - 8 = 12
8 = 12
Hope this help you!!! :)