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o9623199
25.06.2019 •
Mathematics
Crickets can jump with a vertical velocity of up to 14 ft/s. which equation models the height of such a jump, in feet, after t seconds
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Ответ:
h = 147 - 16t^2.
Step-by-step explanation:
Use the following equation of motion
h = ut + 1/2 gt^2 where h = height, u = initial velocity , g = acceleration due to gravity and t = the time.
So here we have:
h = 14t + 1/2 * -32 * t^2
h = 14t - 16t^2
Ответ:
Height of jump, s(t) = 14t - 16.09t²
Step-by-step explanation:
We have equation of motion s = ut + 0.5 at².
For the this vertical motion we have
s = height of jump
u = initial velocity = 14 ft/s
t = time
a = acceleration due to gravity = -32.17 ft/s²
Substituting
s = 14 x t + 0.5 x (-32.17) x t²
s = 14t - 16.09t²
Height of jump, s(t) = 14t - 16.09t²
Ответ:
He spent 1/4 of his paycheck on clothes, that is, = 1/4 *185 = 46.25
$8.25 for lunch.
Total spent = 8.25 + 46.25 = 54.50.
So he spent $ 54.50 of his salary