D(n)=6−4(n−1) find the 5 terms in the sequence

Step-by-step explanation:

There's a proportion relationship between number of shell and their cost

Step-by-step explanation:

The graph is not given.

However, I've added the appropriate graph as an attachment.

From this, point

I'll show that the cost and number of shells as given in the question are proportional.

Represent cost with y and number of shells with x

x = 2 when y = 0.8

x = 3 when y = 1.2

x = 4 when y = 1.6

Divide each value of y by x to get the constant of proportion (r).

r = y/x

r = 0.8/2 = 0.4

r = 1.2/3 = 0.4

r = 1.6/4 = 0.4

Notice that the values of r remain constant.

Hence, there's a proportion relationship between both

And what this rate represent is that:.the cost of shell changes at a constant rate when the number of shell is changes.

The graph is not given.

However, I've added the appropriate graph as an attachment.

From this, point

I'll show that the cost and number of shells as given in the question are proportional.

Represent cost with y and number of shells with x

x = 2 when y = 0.8

x = 3 when y = 1.2

x = 4 when y = 1.6

Divide each value of y by x to get the constant of proportion (r).

r = y/x

r = 0.8/2 = 0.4

r = 1.2/3 = 0.4

r = 1.6/4 = 0.4

Notice that the values of r remain constant.

Hence, there's a proportion relationship between both

And what this rate represent is that:.the cost of shell changes at a constant rate when the number of shell is changes.