Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 a) both are solutions b) neither is a solution. c) it cannot be determined. d) only (-1,9) is a solution.

D)Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This  does not work

We can stop now.  (-2,6) cannot be a solution

I think your answer would be approximately 5, so x ≈ 5 . Forgive me if I'm wrong!