Determine the axis of
symmetry for y=x²+2

x=0

Step-by-step explanation:

The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b/2a

in our case

y=x^2+2

a=1 b=0 c=2

so x=-b/2a=-0/2*1=0

x=0 is axis of symmetry

-8, 7

Step-by-step explanation:

Set up an equation.

x² + x = 56

Set the equation equal to zero and factor.

x² + x - 56 = 0

(x + 8)(x - 7) = 0

Solve for x.

x + 8 = 0

x = -8

x - 7 = 0

x = 7

The possible x values are -8 and 7.