Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x^3/(x-2)(x+1)

for a rational, we find the vertical asymptotes where its denominator is 0, thus

(x-2)(x+1) = 0, gives us two vertical asymptotes when that happens, x = 2 and x = -1.

if we expand the denominator, we'll end  up with a quadratic equation, namely a 2nd degree equation, whilst the numerator is of 3rd degree.  Whenever the numerator has a higher degree than the denominator, the rational has no horizontal asymptotes, however when the numerator is exactly 1 degree higher like in this case, it has an oblique asymptote instead.

The probability is 0%

Step-by-step explanation: Because there's no red marbles in the bag in the first place.