Determine the period of the following graph. 5
4
2
7
a स
5
3.11
8
53
8
31
4
9.31
8
52
4
2
1
-2

9514 1404 393

  π/2

Step-by-step explanation:

The first peak has an x-coordinate of 0. The second peak has an x-coordinate of π/2. The period is the difference of these:

  period = π/2 -0

  period = π/2

4

Step-by-step explanation:

6<x+2 original

6-2<x subtract 2 from both sides

4>x flip the sign because we subtracted from both sides

4>x final, any number greater than 4 is X

checking:

plug in any value greater than 4 into x, for example, lets use 5

6<x+2

6<5+2

6<7   6 is less than 7, this is true the equasion works