Determine the relationships between the following lines: * AB A (2, 5), B(6, – 11)
CĐ C (3, 10), D(-1, 9)

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  the lines are perpendicular

Step-by-step explanation:

You can tell something by looking at the differences of coordinates:

  B-A = (6-2, -11-5) = (4, -16) . . . . . Δy/Δx = -16/4 = -4

  D-C = (-1-3, 9-10) = (-4, -1) . . . . .  Δy/Δx = -1/-4 = 1/4

The product of the slopes of these lines is (-4)(1/4) = -1, so ...

  the lines are perpendicular

a=1

b=-5

c=6

Step-by-step explanation:

ax^2+bx+c=0

Is the formula used for this question.