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hehena
15.10.2019 •
Mathematics
Determine the simple interest. (assume 360 days in a year.)
p= $544, r=0.047% per day, t= 3 months
the simple interest on $544 at 0.047% per day for 3 months is $
(round to the nearest cent.)
.
Solved
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Ответ:
ANSWER:
The simple interest is $23.01 approximately.
SOLUTION:
Given, p= $544, r=0.047% per day, t= 3 months
we need to find the simple interest on $544 at 0.047% per day for 3 months.
We know that,
where, p = principal amount
r = rate of interest
t = number of years
Here, rate and time period are in days and months respectively. But we need to convert both of them into years.
R = 0.047%
360 [since we have to assume there are 360 days in a year]
R = 16.92%
Now t = 3 months
Now, S.I =![$\left(\frac{544 \times 16.92 \times \frac{1}{4}}{100}\right)$](/tpl/images/0321/3254/71e23.png)
Hence, the simple interest is $23.01 approximately.
Ответ:
Step-by-step explanation:
If AB ⊥ CD, then![m_{AB}](/tpl/images/0921/6216/44225.png)
= - 1
P(
,
)
y -
= m( x -
)
~~~~~~~~~~~~~~~~
y = - 2x + 6 and P(3, 3) , m = - 2
Slope of ⊥ line is![\frac{1}{2}](/tpl/images/0921/6216/9cdae.png)
y - 3 =
( x - 3 )
y =
x +
or y = 0.5x + 1.5