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struckedblazing
11.01.2021 •
Mathematics
Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and rounded to the nearest tenth. A (−9, 3), B (−6, −1), C (2, 5), D (−5, 6)
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Ответ:
Perimeter = 5 + 5 + 7.1 + 10 =27.1
area = (5 + 10)x5 / 2 = 37.5
Step-by-step explanation:
Slope formula: m = (x' - x)/(y' - y)
m-AD: (6-3)/(-5 - -9) = 3/4 (I'm not detail other Other slopes)
m- BC = 3/4
m-AB = - 4/3
m-AD = m-BC AD // BC (ABCD is a Trapezoid)
m-AB = - 1 / m-BC
AB ⊥ BC
segment length formula: d = √(x' - x)² + (y' - y)²
AD = √(-5 - -9)² + (6 - 3)² = √4² + 3² = √25 = 5
DC = √50 = 7.1
BC = √100 = 10
AB = √25 = 5
Perimeter = 5 + 5 + 7.1 + 10 =27.1
area = (5 + 10)x5 / 2 = 37.5
area ABCD = (5+10)x5 / 2 =
Ответ: