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sweetbri7p5v6tn
06.09.2020 •
Mathematics
Determine whether the given function is a solution to the given differential equation. x =2cost - 3sint, x'' +x =0
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Ответ:
Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :
Now , second derivative :
( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
Ответ:
The sales person is making 3% so, we would simply multiply $1400 by .03
1400*.03
=$42
They made $42 dollars on a $1400 sale, pretty lousy if you ask me.