Determine which is the graph of the given function.

The answer is second figure

Step-by-step explanation:

f(x) = 3x + 2 ⇒ x < 5

Represented by line its slope = 3 and its y-intercept =2 and end with empty circle on the point x = 5 because x ≠ 5

f(x) = -3x - 2 ⇒ x ≥ 5

Represented by line its slope is -3 and start from x = 5 and y = -17 with black circle on the point x = 5 because x = 5

Step-by-step explanation:

Both terms are perfect squares so factor using the difference in squares formula of a^2-b^2=(a+b)(a-b)

a=6 and b=5a^6b^6

0.04(6+5a^6b^6)(6-6a^6b^6)