Devon decided to rewrite the quadratic equation so that it could be simplified into a square in order to find the zeros.
which process correctly shows devon rewriting x2 +10x+13 into a square?
a) (x2 + 10x + 25) + 13(x + 5)2 +13
b) (x2 + 10x + 25) + 13 - 25(x + 5)2 -12
c) (x2 + 10x + 100) + 13 - 100(x + 10)2 -87
d) x = 10 ± 102 - 4(1)(13)2

Option B

Step-by-step explanation:

Given: x² + 10x + 13

To make a complete square, we will use (b/2)² to add terms to complete the square where b is the coefficient of x

b = 10 , (b/2)² = 5² = 25

So, add 25 and subtract 25

x² + 10x + 13

= x² + 10x + 13 + 25 - 25

= (x² + 10x + 25) + 13 -25

= (x+5)² - 12

By comparing the options with the previous steps

So, the answer is option B

Step-by-step explanation:

im not sure i even tried solving it alone but i dont know the answer im sorry