Do i need to regroup when you subtract 5 from 44

yes

Step-by-step explanation:

you will have to regroup becuase you cant subctract 5 from 4 so you have to regroup.

Someone else had this problem, so I copied the

the first number is -2
the 2nd is 5
the third is 7

Equations:
X+y+z=10
2y-x=12
x-y+2z=7

Try to eliminate y and z by substitution

2y-x=12
2y=12+x
y=6+(1/2)x

x-y+2z=7
2z=7+y-x
z=(1/2)(7+y-x)
and y=6+(1/2)x
z=(1/2)(7+6+(1/2)x-x)
z=(1/2)(13+(-1/2)x)

substitute those
x+y+z=10
x+6+(1/2)x+(1/2)(13+(-1/2)x)=10
x+6+(1/2)x+(13/2)+(-1/4)x=10
(4/4)x+(12/2)+(2/4)x+(13/2)+(-1/4)x=10
(5/4)x+(25/2)=10
minus (25/2) from both sides
(5/4)x=(20/2)-(25/2)
(5/4)x=-5/2
times both sides by 4
5x=-10
divide both sides by 5
x=-2

substitute back

y=6+(1/2)x
y=6+(1/2)(-2)
y=6-1
y=5

z=(1/2)(13+(-1/2)x))
z=(1/2)(13+(-1/2)(-2))
z=(1/2)(13+1)
z=(1/2)(14)
z=7