Mathematics: Do it pls right now . . .

The vertices of the quadrilateral after a dilation with scale factor are , , and .Step-by-step explanation:Let suppose that center of dilation is located at origin, that is . Vectorially speaking, dilation is described by following expression: (1)Where: - Center of dilation. - Original point. - Dilated point. - Dilation factor.If we know that , , , , and , then the dilated points are, respectively:The vertices of the quadrilateral after a dilation with scale factor are , , and ....

Do it pls right now . . . - id11895161, rleiphart1

Ответ:

sobell7725

02.01.2022

Mathematics

The vertices of the quadrilateral after a dilation with scale factor $\frac{2}{3}$ are J'(x,y) = (0,0) , K'(x,y) = (0,4) , L'(x,y) = (6, 8) and M'(x,y) = (8,0) .

Step-by-step explanation:

Let suppose that center of dilation is located at origin, that is O(x,y) = (0,0) . Vectorially speaking, dilation is described by following expression:

$D'(x,y) = O(x,y) + r\cdot [D(x,y)-O(x,y)]$ (1)

Where:

O(x,y) - Center of dilation.

D(x,y) - Original point.

D'(x,y) - Dilated point.

- Dilation factor.

If we know that O(x,y) = (0,0) , $r = \frac{2}{3}$ , J(x,y) = (0,0) , K(x,y) = (0,6) , L(x,y) = (9,12) and M(x,y) = (12,0) , then the dilated points are, respectively:

$J'(x,y) = O(x,y) + r\cdot [J(x,y)-O(x,y)]$

$J'(x,y) = (0,0) +\frac{2}{3}\cdot [(0,0)-(0,0)]$

J'(x,y) = (0,0)

$K'(x,y) = O(x,y) + r\cdot [K(x,y)-O(x,y)]$

$K'(x,y) = (0,0)+\frac{2}{3}\cdot [(0,6)-(0,0)]$

K'(x,y) = (0,4)

$L'(x,y) = O(x,y) +r\cdot [L(x,y)-O(x,y)]$

$L'(x,y) = (0,0) + \frac{2}{3}\cdot [(9,12)-(0,0)]$

L'(x,y) = (6, 8)

$M'(x,y) = O(x,y) +r\cdot [M(x,y)-O(x,y)]$

$M'(x,y) = (0,0) +\frac{2}{3}\cdot [(12,0)-(0,0)]$

M'(x,y) = (8,0)

The vertices of the quadrilateral after a dilation with scale factor $\frac{2}{3}$ are J'(x,y) = (0,0) , K'(x,y) = (0,4) , L'(x,y) = (6, 8) and M'(x,y) = (8,0) .

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