Does anyone know away that i maybe able to understand these problems better

Step-by-step explanation:

Solving for x. Want to solve for f instead?

Step 1 move all terms to one side

fx - 4x² + 100 =0

Step 2 Use the Quadratic Formula

x = -f + √f² + 1600 ÷ -8,   -f-√f²+1600 ÷ -8

Done.

Step-by-step explanation:

a) Given the proportion:

\frac{2}{15}=\frac{3}{2}x

You must solve for "x":

(\frac{2}{3})(\frac{2}{15})=xx=\frac{4}{45}

b) Given:

\frac{9}{4}=\frac{x+2}{x+3}

Solve for "x":

(x+3)(\frac{9}{4})=x+2frac{9}{4}x+\frac{27}{4}=x+2frac{9}{4}x-x=2-\frac{27}{4}frac{5}{4}x=-\frac{19}{4}x=(-\frac{19}{4})(\frac{4}{5})x=-\frac{19}{5}

c) \frac{x+5}{x}=\frac{10}{8}

Solve for "x":

x+5=\frac{10}{8}x5=\frac{10}{8}x-x5=\frac{1}{4}x(5)(4)=xx=20

d) \frac{3x}{21}=\frac{5}{7}

Solve for "x":

3x=(\frac{5}{7})(21)x=\frac{15}{3}x=5

e) \frac{2x-1}{x+2}=\frac{3}{5}

Solve for "x":

(5)(2x-1)=(3)(x+2)10x-5=6x+610x-3x=6+57x=11x=\frac{11}{7}

f) \frac{x-5}{3}=\frac{x-1}{4}

Solve for "x":

(4)(x-5)=(x-1)(3)4x-20=3x-34x-3x=-3+20x=17