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lexhorton2002
12.02.2020 •
Mathematics
Does there exist a Pythagorean triple of the form m, m+7, and m+8, where m is a natural number? If the answer is yes, determine all such Pythagorean triples. If the answer is no, prove that no such Pythagorean triple exists.
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Ответ:
Yes, m = 5
Step-by-step explanation:
m^2 + (m+7)^2 = (m+8)^2 by Pythagorean Theorem. You get m = 5, -3 so m = 5 since -3 is not a natural number.
Ответ:
13/24 extra cups
Step-by-step explanation:
4 2/3 - 4 1/8 = (4 + 2/3) - (4 - 1/8) = 4 + 2/3 - 4 - 1/8 = 2/3 - 1/8 =
= 2*8/3*8 - 1*3/8*3 = 16/24 - 3/24 = 13/24