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pheonixhowls
16.01.2020 •
Mathematics
Drag each trigonometric function to the correct location on the chart.
match the trigonometric functions with their values.
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Ответ:
1.![\frac{\sqrt{3}}{2}](/tpl/images/0458/1635/5848d.png)
2. 0.5
3. 0.5
4.![\frac{\sqrt{3}}{2}](/tpl/images/0458/1635/5848d.png)
5. 0.5
6. 0.5
Step-by-step explanation:
Here we have to match the trigonometric functions with their values.
Now,
(1)![\sin \frac{\pi }{3} = \sin 60^{\circ} = \frac{\sqrt{3}}{2}](/tpl/images/0458/1635/1d368.png)
(2)![\sin \frac{\pi }{6} = \sin 30^{\circ} = 0.5](/tpl/images/0458/1635/02474.png)
(3)![\cos \frac{\pi }{3} = \cos 60^{\circ} = 0.5](/tpl/images/0458/1635/5f798.png)
(4)![\cos \frac{\pi }{6} = \cos 30^{\circ} = \frac{\sqrt{3}}{2}](/tpl/images/0458/1635/b4b8b.png)
(5)![\cos \frac{5\pi}{3} = \cos (2\pi - \frac{\pi}{3}) = \cos \frac{\pi}{3} = \cos 60^{\circ} = 0.5](/tpl/images/0458/1635/ff3a4.png)
(6)![\sin \frac{5\pi}{6} = \sin (\pi - \frac{\pi}{6}) = \sin \frac{\pi}{6} = \sin 30^{\circ} = 0.5](/tpl/images/0458/1635/36dc1.png)
{Since,
and
} (Answer)
Ответ:
y = –3x2 – 12x – 2
1/3(y + 2) =- (x +2)^2
1/3(y + 2)=- (x +2)^2 +4
1/3 y +2/3 = - (x +2)^2 +4
1/3 y = - (x +2)^2 +10/3
y = -3(x +2)^2 + 10
answer is a.