Mathematics: Drag values to complete each equation.

Drag values to complete each equation. - id1170544, penelopegrace04

emilydis2594

14.03.2022

a. $((12)^2)^3\cdot (12)^{-4}=12^2$

b. $\frac{(12)^7\cdot (12)^{-5}}{(12)^2}=1$

Step-by-step explanation:

We have to complete each equation

We are given that

$((12)^2)^3\cdot (12)^{-4}$

$(12)^6\cdot (12)^{-4}$

Using identity

$(a^x)^y=a^{xy}$

$(12)^{6-4}=(12)^2$

Using identity: $a^x\cdot a^y=a^{x+y}$

$((12)^2)^3\cdot (12)^{-4}=12^2$

b. $\frac{(12)^7\cdot (12)^{-5}}{(12)^2}$

$\frac{(12)^2}{(12)^2}$

$(12)^{2-2}=(12)^0=1$

Using identity: $\frac{a^x}{a^y}=a^{x-y},a^0=1$

$\frac{(12)^7\cdot (12)^{-5}}{(12)^2}=1$

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JoeWeiss674

22.05.2021

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▹ Answer

▹ Step-by-Step Explanation

3³ + 4²

= 27 + 16

= 43

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

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