mateotrevino1
11.04.2021 •
Mathematics
Each salad contains red beans, Lima beans, and black eyed beans. Use the information below to determine how many of each of the three types of beans are needed
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Ответ:
A.) Black eyed beans = at least 3 ; Red beans = atleast 4 ; Lima beans = atleast 5
B.) Red and Lima beans = 5 each ; Black eyed beans = 8
C.) Lima beans = 4 ; Black eyed beans = 2 ; Red beans = 2
Step-by-step explanation:
Let :
Black eyed beans = x
Red beans = x + 1
Lima beans = x + 1 +1 = x + 2
Total beans is atleast 12
x + (x +1) + (x + 2) ≥ 12
x + x + 1 + x + 2 ≥ 12
3x + 3 ≥ 12
3x ≥ 9
x ≥ 3
Black eyed beans = at least 3
Red beans = atleast 4
Lima beans = atleast 5
B.)
Same number of Red and Lima beans
Black eyed beans is 3 more than red beans
Total beans = 18
Red and Lima = x + x
Black eyed beans = x + 3
x + x + x + 3 = 18
3x + 3 = 18
3x = 18 - 3
3x = 15
x = 5
Red and Lima beans = 5 each
Black eyed beans = 3 + 5 = 8
C.)
Total beans in salad = x
Number of red beans = 2
Lima beans = 2 * 2 = 4
Lima beans = 1/2 of x ; x/2
4 = x /2
8 = x = total beans in salad
Red + lima + black eyed = 8
2 + 4 + black-eyed = 8
Black eyed beans = 8 - 6 = 2
Lima beans = 4
Black eyed beans = 2
Red beans = 2
Ответ:
N being Nelson's score.