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15.08.2020 •
Mathematics
El recibo del servicio de celular del mes de abril facturó un monto de S/52,50 por un consumo de 69 minutos; y el del mes de mayo, facturó S/32 por un consumo de 28 minutos. El monto que cobran cada mes incluye un costo fijo por mantenimiento y un precio establecido por minuto de consumo. ¿Cuántos minutos se debería consumir como máximo para pagar menos de S/30 el siguiente mes?
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Ответ:
x = 24 minutos
Step-by-step explanation:
Llamaremos "y" el costo fijo mensual y "x" la cantidad de minutos consumidos al mes, según lo cual:
El enunciado del problema establece que la facturación en pesos es igual a un costo fijo y más el consumo en minutos del mes, entonces
En Abril 52,50 = y + b*x ⇒ 52,5 = y + 69*b
y en Mayo 32 = y + b*x ⇒ 32 = y + 28*b
Así obtuvimos un sistema de dos ecuaciones con dos incógnitas, que resolveremos y obtendremos los valores de b y de y
y = 52,50 - 69*b
32 = ( 52,50 - 69*b ) + 28*b
- 20,50 = - 41*b
b = 0,5
y y = 52,5 - 69*0,5
y = 18
Entonces la ecuación de facturación es :
F(x) = 18 + 0,5*x
Para pagar como máximo 30 pesos en el mes siguiente
F(x) = 30 = 18 + 0,5*x
30 - 18 = 0,5*x
x = 24 minutos
Ответ:
Key Steps in Finding the Inverse Function of a Quadratic Function. Replace f ( x ) f(x) f(x) by y. Switch the roles of x and y. In other words, interchange x and y in the equation