shealynh52
31.03.2021 •
Mathematics
En una tienda en la que todo está rebajado el 20% he comprado una casaca por la que he pagado 160 soles. ¿Cuál era el precio antes de la rebaja?
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Ответ:
200 soles
Step-by-step explanation:
De la pregunta anterior, se nos da un descuento del 20%.
Por lo tanto, la fórmula para resolver la pregunta anterior es:
Precio nuevo = Precio inicial - (Porcentaje de descuento × Precio inicial)
De la pregunta anterior,
Precio nuevo = 160 soles
Precio inicial = x
Porcentaje de descuento = 20% = 0.2
Por eso:
160 = x - (20% x x)
160 = x - 0.2x
160 = 0.8 veces
Dividir ambos lados por 0.8
160 / 0.8 = 0.8 / 0.8
x = 160 / 0.8
x = 200 soles
Por lo tanto, el Precio Inicial que es el precio antes de la venta es de 200 soles.
Ответ:
Step-by-step explanation:
Given :
Month: # of orders in # of orders out:
January (1) 3 3
February (2) 6 4
March (3) 9 5
April (4) 12 6
The solution may be found by graphing the data.
You can graph the number of orders in and the number of orders out, as a function of the month in a same coordinate system
The solutions are:
y = 3 x (purple line on graph), where y is the number of orders in, and x is the number of the month
z= x + 2,(black line on graph) where z is the number of orders out, and x is the number of the month.
Since the order in and out are same in the first month so
⇒3 x= x+2
Put x=1 (1 month)
⇒3=3
HENCE VERIFIED
The equations are true to the situation