Mathematics: Enter the equation of the circle described below. center (-1, 4), radius = √3

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Enter the equation of the circle described below.

nsuleban8663

04.01.2022

The equation of circle with Center (-1, 4), radius = √3 is (x+1)^2+(y-4)^2=3

Step-by-step explanation:

Given : Center (-1, 4), radius = √3

We have to find the equation of circle with Center (-1, 4), radius = √3.

The standard equation of circle with center (h,k) and radius r is given by

(x-h)^2+(y-k)^2=r^2 ,

Given Center (-1, 4), radius = √3

Subsitute, h = -1 , k = 4 and r = √3

We have,

$(x-(-1))^2+(y-4)^2=(\sqrt{3})^2$

Simplify, we have,

(x+1)^2+(y-4)^2=3

Thus, The equation of circle with Center (-1, 4), radius = √3 is (x+1)^2+(y-4)^2=3

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