Enter valeues to complete the table below

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sarahalexa19

17.06.2022

Mathematics

$h(x)=\dfrac{4+4x}{5+x}\\\\\text{substitute x+2}\\\\h(x+2)=\dfrac{4+4(x+2)}{5+(x+2)}=\dfrac{4+4x+8}{5+x+2}=\dfrac{4x+12}{x+7}$

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