Es
estimate the size of a crowd at an airshow that occupies a rectangular space with dimensions of 500 feet by 750 feet (to the
nearest whole number).
assume that each person occupies 9 square feet.
10,417 people
20,833 people
41,667 people
83,333 people

1 / y^22

Step-by-step explanation:

We multiply bracket powers and add powers if no brackets when multiplying same numbers on same line (denominator with denominator and numerator with numerator, we could cross multiply with (y^7)^6 / (y^7)^6 but workings below show when we simplify then subtract powers last step to reduce the fraction with no action of cross multiply.

(y^4 )^5 = y^20

(y^7)^6 = y^42

= y^20/ y^42

= 1 / y^22