Et r be the size of a population of rabbits, and s the population of sheep in the same area. the lotka–volterra competition model for these species might look like the following: r = 24r − 2r^2 − 3rss = 15s − s^2 − 3rsa) plot the nullclines of this system.b) use the nullclines and/or algebra to find the equilibrium points of the system.c) sketch the direction of the change vectors along each nullcline. then, fill in the change vectors in the rest of the vector field.d) use your sketch of the vector field to determine the type of each equilibrium point.e) how many stable equilibrium points are there? draw a rough estimate of the basin of attraction of each one. based on this, what one-word description could you give to this system?

4 miles

Step-by-step explanation:

Lets start by trying to get the rates of walk and bike.

We know Dave walks at a rate of 4 mph, so, it takes him 60 minutes to walk 4 miles. We can use this proportion to find out how much times takes him to walk 1 mile:

60/4 = 15/1 = Rw

So, his rate for walking is 1 mile each 15 minutes, or, 15 minutes per mile.

Now we do the same for biking, as he bikes at 10 mph. He then bikes 10 miles per 60 minutes:

60/10 = 6

So, he bikes 1 mile each 6 minutes, or, he needs 6 minutes for per mile.

If x is the distance he walked and y the one the biked (in miles), 15x is the time it takes to walk the distance and 6y the time it takes to bike the distance.

We know that the time it took him to walk is 18 minutes greater than the time that took him to bike, so:

18 + 6y = 15x

But as he traveled between 2 points, the distances are the same, x=y, so:

18 + 6x = 15x

Subtracting 6x in both sides:

18 = 9x

Dividing by 9 in both:

2 = x

So, the distance to his friend's house is 2 miles, and the back distance is also 2 miles. Thus, the trip has a distance of 4 miles.