Mathematics: Evaluat 1/2^-2x^-3y^5 for x=2 and y=-4

Evaluat 1/2^-2x^-3y^5 for x=2 and y=-4 - id12235245211354, KekePonds1021

Ответ:

huntbuck14

19.01.2022

Mathematics

-1/32

Step-by-step explanation:

1/(2⁻²x⁻³y⁵)

x=2

y=-4

1/(2⁻²x⁻³y⁵) = 1/(2⁻²2⁻³-4⁵)

4= 2²

equate it back where 4 is

1/(2⁻²2⁻³2²⁽⁵⁾) = 1/(2⁻²2⁻³2¹⁰)

using law of indices

1/(2⁻²⁺⁽⁻³⁾+¹⁰) = 1/(2⁻²⁻³⁺¹⁰) = 1/2⁻⁵⁺¹⁰= 1/2⁻⁵ = -1/2x2x2x2x2 = -1/32

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Ответ:

epicriderexe

19.01.2022

Mathematics

$-\frac{1}{32}$

Step-by-step explanation:

Given Equation:

$\frac{1}{2^-^2*x^-^3*y^5}$

Multiplying numerator and denominator by 2^2*x^3 gives:

$\frac{2^2*x^3}{y^5}$

We have to evaluate the equation at x=2 and y=-4

Putting the values of x and y in the equation:

= $\frac{2^2*2^3}{(-4)^5}$

= $\frac{4*8}{(-1024)}$

= $-\frac{32}{1024} \\$

= $-\frac{1}{32}$

On putting the value of 'x' and 'y' in the equation the solution of the equation is $-\frac{1}{32}$

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Ответ:

paulitaaustin

19.05.2021

Mathematics

d i think

Step-by-step explanation:

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Evaluat 1/2^-2x^-3y^5 for x=2 and y=-4

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