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06.01.2020 •
Mathematics
Evaluate ic2 + b2l, given a = 5, b = -3, and c= -2.
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Ответ:
Ic² + b²l = 13 units.
Step-by-step explanation:
We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.
Now, Ic² + b²l
= I(- 2)² + (- 3)²l {Putting the values of b and c}
= I4 + 9l
= I13l
= 13 units.
Therefore, Ic² + b²l = 13 units. (Answer)
Ответ:
2. prime
3. (t - 16) (t + 3) t = 16 and -3
4. prime
5. (t + 15) (t - 2) t = -15 and 2