Explain how you know if an ordered pair is a solution to an equation or not.
(Please use your words and math, with an example.)

You can plug in the pair into the equation

Step-by-step explanation:

You take the ordered pair and plug it into the equation. If it matches, that is your solution

For example:  y=2x+1 .  Pair:  (1,3)

Plug 3 for y and 1 for x.  3=2(1)+1 is 3

Step-by-step explanation:

x^4 – 16x^3 + 96x^2 – 256x + 256

terms with odd exponents are negative

x^4 has a coefficient of one, so the expression's GCF is 1

Thus, we need to factor out the expression as it is:

(x-4)*(x-4)*(x-4)*(x-4)

Lets multiply it out to check:

(x-4)*(x-4)*(x-4)*(x-4)=

(x^2-8x+16)*(x^2-8x+16)=

x^4−8x^3+16x^2−8x^3+64x^2−128x+16x^2−128x+256=

x^4 – 16x^3 + 96x^2 – 256x + 256

thus, the factored form is:

(x-4)*(x-4)*(x-4)*(x-4) or (x-4)^4