Mathematics: Explain why the columns of an n times n matrix a are linearly independent when a has an inverse.

[tex]y = (x-2)^2 - 15[/tex]general transformations: [tex]y = a(x-h)^2 + k[/tex]is a horizontal translations of [tex]h[/tex] units (to the right if h is positive, to the left if h is negative) and a vertical translation of [tex]k[/tex] units (up if k is positive, down if k is negative). a is vertical stretches, but they do not apply here.for [tex]y = (x-2)^2 - 15[/tex], h = 2 and k = -15.so translate [tex]y=x^2[/tex] two units to the right and fifteen units down.....

Explain why the columns of an n times n matrix a

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boo2023

14.01.2022

Mathematics

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Explain why the columns of an n times n matrix a are linearly independent when a has an inverse.

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sushiboy668

07.06.2021

Mathematics

$y = (x-2)^2 - 15$ general transformations: $y = a(x-h)^2 + k$ is a horizontal translations of $h$ units (to the right if h is positive, to the left if h is negative) and a vertical translation of $k$ units (up if k is positive, down if k is negative). a is vertical stretches, but they do not apply here.for $y = (x-2)^2 - 15$ , h = 2 and k = -15.so translate $y=x^2$ two units to the right and fifteen units down..

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Explain why the columns of an n times n matrix a are linearly independent when a has an inverse.

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