Explain why x=4 is not in the domain of the function f(x)=√x-5 ?

Since we are dealing with a radical then x - 5 ≥ 0, for real values

x = 4 is less than 5 , hence is not in the domain

  4 + 22x − 1 = 0

Step-by-step explanation:

Start off with the standard formula to finding area with polynomials and quadratic functions.

(2x + 5)(2x + 6)

Work out like a normal binomial.

4 + 22x + 30 - 31

(You're subtracting 31 to take out the minimum of what the frame has to be)

4 + 22x - 1 = 0